Discussion:
[Tutor] Help Command Question
l***@gmail.com
2015-07-28 17:00:37 UTC
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Hi Everyone,


I'm trying to print a command of list options by using the help command in the iPython interpreter. Read captured copy of the printout as follows:



'Python 2.7.10 |Anaconda 2.3.0 (64-bit)| (default, May 28 2015, 16:44:52) [MSC v.
1500 64 bit (AMD64)]
Type "copyright", "credits" or "license" for more information.


IPython 3.2.0 -- An enhanced Interactive Python.
Anaconda is brought to you by Continuum Analytics.
Please check out: http://continuum.io/thanks and https://anaconda.org




In [1]: help list
File "<ipython-input-1-823a3ff84bc4>", line 1
help list
^
SyntaxError: invalid syntax.'


Question: What is the correct help command?


Regards,

Hal






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Martin A. Brown
2015-07-28 17:44:20 UTC
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Hi there,
Post by l***@gmail.com
In [1]: help list
File "<ipython-input-1-823a3ff84bc4>", line 1
help list
^
SyntaxError: invalid syntax.'
Question: What is the correct help command?
Try:

help(list)

Snipped from my ipython session:

In [1]: help(list)

Good luck,

-Martin
--
Martin A. Brown
http://linux-ip.net/
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Mark Lawrence
2015-07-28 17:59:50 UTC
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Post by l***@gmail.com
Hi Everyone,
'Python 2.7.10 |Anaconda 2.3.0 (64-bit)| (default, May 28 2015, 16:44:52) [MSC v.
1500 64 bit (AMD64)]
Type "copyright", "credits" or "license" for more information.
IPython 3.2.0 -- An enhanced Interactive Python.
Anaconda is brought to you by Continuum Analytics.
Please check out: http://continuum.io/thanks and https://anaconda.org
In [1]: help list
File "<ipython-input-1-823a3ff84bc4>", line 1
help list
^
SyntaxError: invalid syntax.'
Question: What is the correct help command?
Standard iPython says this.

Python 3.4.3 (v3.4.3:9b73f1c3e601, Feb 24 2015, 22:44:40) [MSC v.1600 64
bit (AMD64)]
Type "copyright", "credits" or "license" for more information.

IPython 3.2.0 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.

In [1]: list?
Docstring:
list() -> new empty list
list(iterable) -> new list initialized from iterable's items
Type: type

In [2]: list??
Docstring:
list() -> new empty list
list(iterable) -> new list initialized from iterable's items
Type: type

In [3]: help(list)
Help on class list in module builtins:

class list(object)
| list() -> new empty list
| list(iterable) -> new list initialized from iterable's items
|
| Methods defined here:
|
| __add__(self, value, /)
| Return self+value.
...

Got it?
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence

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